answer:Let's denote the three consecutive odd integers as (x), (x+2), and (x+4). According to the problem, the third integer is 15, so (x+4 = 15). Now we can solve for (x): (x + 4 = 15) (x = 15 - 4) (x = 11) So the first integer is 11, the second is 13, and the third is 15. The problem states that 3 times the first integer is a certain number more than twice the third. So we have: (3 times x = 2 times (x+4) + text{certain number}) We already know that (x = 11) and (x+4 = 15), so we can plug these values in: (3 times 11 = 2 times 15 + text{certain number}) (33 = 30 + text{certain number}) The "certain number" is the difference we are looking for: (text{certain number} = 33 - 30) (text{certain number} = 3) Therefore, the difference between 3 times the first integer (11) and twice the third integer (15) is boxed{3} .

answer:Given A={1,2} and B={-a, a^{2}+3}, with the condition that Acup B={1,2,4}, we proceed to find the value of a. We examine the two possibilities for elements in B to match the union set: 1. **Case 1:** -a=4 This leads us to the equation: -a = 4 implies a = -4 Substituting a=-4 into B, we get: B = {-(-4), (-4)^{2}+3} = {4, 19} However, Acup B = {1,2,4,19}, which contradicts the given condition Acup B={1,2,4}. Therefore, this case is discarded. 2. **Case 2:** a^{2}+3=4 Solving this equation, we get: a^{2} + 3 = 4 implies a^{2} = 1 implies a = pm 1 When a=1: B = {-1, 1^{2}+3} = {-1, 4} However, Acup B = {1,2,-1,4}, which again contradicts the given condition. Thus, this scenario is also discarded. When a=-1: B = {1, (-1)^{2}+3} = {1, 4} In this case, Acup B = {1,2,4} matches exactly with the given condition, satisfying the requirements of the problem. Hence, the value of a that meets the problem's criteria is a=-1. Therefore, the answer is: boxed{-1}.

answer:To solve this problem, we start by understanding the relationship between the number of tickets sold for the horror movie and the romance movie. The problem states that the number of tickets sold for the horror movie is 18 more than three times the number of tickets sold for the romance movie. Given that the number of tickets sold for the romance movie is 25, we can calculate the number of tickets sold for the horror movie as follows: First, we calculate three times the number of tickets sold for the romance movie: [ 3 times 25 = 75 ] Next, we add 18 to this number to find the total number of tickets sold for the horror movie: [ 75 + 18 = 93 ] Therefore, the movie theater sold boxed{93} tickets to the horror movie.

answer:To find the value in the list for which 0.36363636363636365 of the data is less than it, we need to determine the position of this value in the sorted list. First, let's find the total number of data points in the list: 1, 2, 3, 4, 5, 5, 5, 5, 7, 11, 21 There are 11 data points. Now, we multiply the total number of data points by the fraction to find the position: 11 * 0.36363636363636365 ≈ 4 (since we are looking for a position in a list, we round to the nearest whole number) This means we are looking for the 4th value in the sorted list when counting from the smallest value upwards. The list is already sorted, so the 4th value is 4. Therefore, the value in the list for which approximately 36.36% of the data is less than it is boxed{4} .