answer:If each wolf needs to kill 1 deer, and each deer contains 200 pounds of meat, then each wolf would have 200 pounds of meat to eat. Since the pack contains 16 additional wolves plus the 4 wolves out hunting, there are a total of 20 wolves in the pack. If the wolves won't hunt again for five days, we need to divide the total amount of meat each wolf has by 5 to find out how much meat each wolf needs to eat a day. So, each wolf would need to eat: 200 pounds of meat / 5 days = boxed{40} pounds of meat per day.

answer:If Megan can finish 8 problems in an hour and it took her 8 hours to finish all the problems, then she finished a total of 8 problems/hour * 8 hours = 64 problems. Since we know she had 36 math problems, we can subtract that from the total number of problems she finished to find out how many spelling problems she had. 64 total problems - 36 math problems = 28 spelling problems. So, Megan had boxed{28} spelling problems.

answer:To find the fifth-largest divisor of 1,020,000,000, start with its prime factorization. 1. **Prime Factorization of 1,020,000,000:** - Since 1,020,000,000 = 1020 times 10^6 = (2^2 times 3 times 5 times 17) times (10^6), using 10^6 = (2 times 5)^6, [ 1,020,000,000 = 2^{2} times 3 times 5 times 17 times 2^6 times 5^6 = 2^8 times 5^7 times 3 times 17 ] 2. **Identifying the Largest Divisors:** - The largest divisor is the number itself: 1,020,000,000. - The second-largest divisor, removing the smallest prime factor, which is 2: [ frac{1,020,000,000}{2} = 510,000,000 ] - The third-largest divisor, removing another factor of 2: [ 255,000,000 ] - The fourth-largest divisor, removing one more factor of 2: [ 127,500,000 ] - The fifth-largest divisor, removing another factor of 2: [ 63,750,000 ] 3. **Conclusion:** - The fifth-largest divisor of 1,020,000,000 is 63,750,000. The final answer is boxed{textbf {(B) } 63,750,000}

answer:To find the discount, we first need to calculate the cost price before the brokerage is added. Let's denote the discount as D. The cost price of the stock after the discount and before the brokerage is added would be: 100 - D Since there is a brokerage fee of 1/5%, we need to add this fee to the cost price to get the final cost price of Rs 95.2. The brokerage fee on the cost price (100 - D) would be: (1/5)% of (100 - D) = (1/5)/100 * (100 - D) = (1/500) * (100 - D) Now, the final cost price including the brokerage fee would be: (100 - D) + (1/500) * (100 - D) = 95.2 Let's solve for D: (100 - D) + (1/500) * (100 - D) = 95.2 (100 - D) * (1 + 1/500) = 95.2 (100 - D) * (500/500 + 1/500) = 95.2 (100 - D) * (501/500) = 95.2 Now, we can solve for (100 - D): (100 - D) = 95.2 * (500/501) (100 - D) = 95.2 * (500/501) Now, we can calculate the value of (100 - D): (100 - D) = 95.2 * (500/501) (100 - D) = 95.2 * 500 / 501 (100 - D) = 47600 / 501 (100 - D) ≈ 95.00998 Now, we can find the discount D: D = 100 - 95.00998 D ≈ 4.99002 Therefore, the discount is approximately Rs boxed{4.99} .