answer:First, let's calculate Amanda's regular pay for the first 8 hours and her overtime pay for the additional 2 hours. Regular pay for 8 hours: 8 hours * 50/hour = 400 Overtime pay for 2 hours: Overtime rate = 1.5 * 50/hour = 75/hour 2 hours * 75/hour = 150 Now, let's add her commission to her total earnings for the day: Total earnings without penalty = Regular pay + Overtime pay + Commission Total earnings without penalty = 400 + 150 + 150 Total earnings without penalty = 700 If Jose threatens to withhold 20% of her pay for not finishing the sales report by midnight, we need to calculate the penalty amount and subtract it from her total earnings. Penalty amount = 20% of total earnings Penalty amount = 0.20 * 700 Penalty amount = 140 Now, let's subtract the penalty from her total earnings to find out how much she will receive: Total earnings with penalty = Total earnings without penalty - Penalty amount Total earnings with penalty = 700 - 140 Total earnings with penalty = 560 Therefore, if Amanda does not finish the sales report by midnight, she will receive boxed{560} for the day's work.

answer:First, we understand the structure of the 4-inch cube. It consists of a 4x4x4 arrangement of one-inch cubes, totaling 64 cubes. - **Cubes with three blue faces:** These will be the cubes at the eight corners of the larger cube. Each corner of a cube has three faces exposed, so there are 8 such cubes. - **Cubes with two blue faces:** These cubes are located along the edges of the cube, excluding the corner cubes already counted. Each edge of the cube contains 4 cubes, but excluding the two corners, 2 remain in the middle of each edge with two faces painted. There are 12 edges in a cube, thus (12 times 2 = 24) cubes with two blue faces. Adding these, we find (8) cubes with three faces painted and (24) cubes with two faces painted. Thus, the total number of cubes with at least two faces painted is (8 + 24 = boxed{32}).

answer:Let x = frac{1 - u^4}{1 + u^4} and y = frac{2u^2}{1 + u^4}. Then, [ x^2 + y^2 = left(frac{1 - u^4}{1 + u^4}right)^2 + left(frac{2u^2}{1 + u^4}right)^2. ] Simplify this as, [ x^2 + y^2 = frac{(1 - u^4)^2}{(1 + u^4)^2} + frac{4u^4}{(1 + u^4)^2}. ] Combine the numerator, [ x^2 + y^2 = frac{1 - 2u^4 + u^8 + 4u^4}{(1 + u^4)^2} = frac{1 + 2u^4 + u^8}{(1 + u^4)^2}. ] The numerator (1 + 2u^4 + u^8) can be re-written as (1 + u^4)^2. So, [ x^2 + y^2 = frac{(1 + u^4)^2}{(1 + u^4)^2} = 1. ] Thus, all the plotted points lie on a circle. The answer is boxed{text{(B)}}.

answer:In the function y=a^{x}+2, When x=0, y=a^{0}+2=3. Thus, the graph of the function y=a^{x}+2 must pass through the point (0,3). Therefore, the answer is: boxed{(0,3)}. This solution is derived from the properties of exponential functions and the value of x that is independent of a, thus finding the fixed point that the function graph always passes through. This question primarily tests understanding of the fixed points that exponential functions pass through, with the key to solving being the value of x that is independent of a. This is a basic level problem.